view python/open.py @ 694:ebca6d85213a

File "/usr/lib/python3/dist-packages/IPython/config/__init__.py", line 16, in <module> from .application import * File "/usr/lib/python3/dist-packages/IPython/config/application.py", line 31, in <module> from IPython.config.configurable import SingletonConfigurable File "/usr/lib/python3/dist-packages/IPython/config/configurable.py", line 33, in <module> from IPython.utils.text import indent, wrap_paragraphs File "/usr/lib/python3/dist-packages/IPython/utils/text.py", line 28, in <module> from IPython.external.path import path File "/usr/lib/python3/dist-packages/IPython/external/path/__init__.py", line 2, in <module> from path import * File "/home/jhammel/python/path.py", line 25 print root(path) ^
author Jeff Hammel <k0scist@gmail.com>
date Wed, 09 Jul 2014 16:26:49 -0700
parents 2025368488ee
children
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def load(resource):
    """
    open a file or URL for reading.  If the passed resource string is not a URL,
    or begins with 'file://', return a ``file``.  Otherwise, return the
    result of urllib2.urlopen()
    """

    # handle file URLs separately due to python stdlib limitations
    if resource.startswith('file://'):
        resource = resource[len('file://'):]

    if not is_url(resource):
        # if no scheme is given, it is a file path
        return file(resource)

    return urllib2.urlopen(resource)